Question

express the complex number in the form of a+ iota b


1.) (1- iota )^4

2.)[ 1/3+ 3 iota ] ^3

Answer 1

ĀNSWĒR ⏬⏬

1.) (1- iota )^4

= -4 + 0 iota where a= -4 and b = 0


2.) 242/27 , -26 iota where a= 242/27 or b = -26 iota



for full solution check out the above attachment

I hope it will help you^_^

Thanks ❤:)

#Nishu HarYanvi ♥

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer...

⤵️⤵️⤵️⤵️⤵️

(1-i)^4
This can be written as ((1-i)^2)^2
To solve it you should learn the formula (a-b)^2=(a^2+b^2-2ab) and (i)^2=-1.
Applying the formula we get-
(1+i^2-2i)^2=(1+(-1)-2i)^2=(-2i)^2=
(4(i)^2)=-4