express the denominator of 23÷20 in the form of 2^n×5^m and state whether the given fraction is Terminating or non Terminating repeating decimal
Answers
Given:
Expression 23 20.
To find:
Denominator in the form of and finding whether the given fraction is terminating or non terminating repeating decimal.
Solution:
The denominator of 23 20 is 20.
Let us factorize 20 now:
Now, let us compare factors of 20 with .
=
So, 20 can be represented as .
Let us learn what are terminating fractions and non terminating repeating decimal.
Terminating fractions mean the form which can be completely divided and can be represented in decimal form.
For example:
Non terminating repeating decimal mean the form , when represented in decimal form, the division does not get terminated and there is a repeating digit.
For example:
Here, 3 is the repeating number.
Given fraction is:
The given fraction is terminating.
The denominator 20 in the form of is .
Step-by-step explanation:
We have to express the denominator of 23 ÷ 20 in the form of 2^n × 5^m.
As it is clear that 20 is the denominator of the given fraction. So, finding the factors of 20 by using prime factorization method we get;
20 = 2 10
10 = 2 5
5 = 5 1
So, the factors of 20 = 2 2 5 = .
If we compare this with the form of , we can observe that the value of n = 2 and that of m = 1.
So, the denominator 20 in the form of is .
The given fraction is terminating because when we divide this fraction we get the value of 1.15 which represents that the decimal expansion is terminating after two decimal points.