Express the following as a product of prime factors a) 48 b) 160 c) 182 d) 512
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Answered by
32
Hi friend!!!
The prime factors of 48=2×2×2×2×3
b).160=2×2×2×2×2×5
c).182=2×7×13
d).512=2×2×2×2×2×2×2×2×2
I hope this will help u ;)
The prime factors of 48=2×2×2×2×3
b).160=2×2×2×2×2×5
c).182=2×7×13
d).512=2×2×2×2×2×2×2×2×2
I hope this will help u ;)
Arush21:
thanks
Answered by
10
Hi friend,
Prime factors of
(a)48 = 2×2×2×2×3 = 2⁴×3
(b)160=2×2×2×2×2×5 = 2^5 × 5
(c)182=2×7×13 = 2¹×7¹×13¹
(d)512=2×2×2×2×2×2×2×2×2 = 2^8
Hope it helps...
Prime factors of
(a)48 = 2×2×2×2×3 = 2⁴×3
(b)160=2×2×2×2×2×5 = 2^5 × 5
(c)182=2×7×13 = 2¹×7¹×13¹
(d)512=2×2×2×2×2×2×2×2×2 = 2^8
Hope it helps...
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