Express the following as a product of prime factors only in the exponential form
(ii) [(22)3 x36] x56
Answers
Answered by
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Answer:
2⁶ × 3³ × 7 ×11
Step-by-step explanation:
(ii) [(22)3 x36] x56
=[ (2× 11)×3 × 36] × 56
=[ 2× 11 × 3 ×2 × 2 × 3 × 3 ] × 56
= ( 2³× 3³× 11) × 2 × 2 × 2 × 7
= 2³× 3³ × 11 × 2³ × 7
= 2⁶ × 3³ × 7 ×11
Answered by
0
Answer:
2⁸×3²×7×11³
Step-by-step explanation:
[(22)³×36]×56
= 22³×36×56
= 2³×11³ ×(36×56)
= 2³×11³ × (2×2×3×3×2×2×2×7)
= 2³×11³ × (2×2×2×2×2×3×3×7)
= 2³×11³×(2⁵×3²×7)
= 2³×11³×2⁵×3²×7
= 2³×2⁵×3²×7×11³
= 2⁸×3²×7×11³
Hence [(22)³×36]×56 as prime factor's exponential form =
2⁸×3²×7×11³
hope it helps.
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