Question

express the following as a sum or a difference of two trigonometric function 2cos4θ cos2θ​

Help me guys I will mark the ans. as brainliest

Answer 1

Answer:

Step-by-step explanation:

//We know that

Cos(A+B) = CosACosB - SinASinB

Cos(A-B) = CosACosB + SinASinB

=> 2CosACosB = Cos(A+B) + Cos(A-B)

So,

2Cos4θCos2θ = Cos(4θ+2θ) + Cos(4θ-2θ)

                        = Cos6θ + Cos2θ.