Express the following as a trigonometric ratio of an angle less than 45°.
sec 63°10'
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sec 63.10° = 1/cos(63.10°)
cos 63.10° = cos (90 - 26.90)° = sin 26.90°
[Since cos(90 - x) = sin x ]
Therefore ,
sec 63.10° = 1/sin(26.90°) = cosec 26.90°
cos 63.10° = cos (90 - 26.90)° = sin 26.90°
[Since cos(90 - x) = sin x ]
Therefore ,
sec 63.10° = 1/sin(26.90°) = cosec 26.90°
yen13muzicp96kj4:
Hi, thanks for your answer, but to make the question clear, it's asking to solve secant 63 degrees 10 prime not 63.10 degrees.
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