Question

express the following as product.



Sin6 tita + sin 4 tita

Answer 1

this is the correct answer

Answer 2

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Ans:.✍️✍️✍️✍️✍️✍️✍️✍️

Given,

$\sin(6 \: tita) + \sin(4 \: tita)$

$= \sin(c) + \sin(d) = 2 \sin( \frac{c + d}{2} ) \cos( \frac{c - d}{2} )$

$= 2 \sin( \frac{6tita + 4tita}{2} ) \cos( \frac{6tita - 4tita}{2} )$


$= 2 \sin( \frac{10tita}{2} ) \cos( \frac{2tita}{2} )$

$= 2 \sin(5 \: tita) \cos(tita)$

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