Question

Express the following as the sum of two consecutive natural numbers. 13 square​

Answer 1

Answer:

84,85

Step-by-step explanation:

one consective natural number be x

other consective natural number be (x+1)

Let

x+x+1=(13)^2

x+x+1=169

2x=169-1

2x=168

x=84

one consective natural number =84

other consective natural number =84+1

85

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Answer 2

☆Answer☆

$\sf {{13}^{2} }$= 84 + 85

Step-by-step explanation-

We have to use given formula-

$\huge\rm\red {{n}^{2} = \frac{ {n}^{2} - 1}{2} + \frac{ {n}^{2} + 1 }{2}}$

• ${{n}^{2}}$ = given natural number ( 13^2)

Now, putting values

$\huge\sf\blue { {13}^{2} = \frac{ {13}^{2} - 1}{2} + \frac{ {13}^{2} + 1 }{2}}$

$\sf {=>{13}^{2} = \frac{169- 1}{2} + \frac{169 + 1}{2}}$

$\sf { =>{13}^{2} = \frac{168}{2} + \frac{170}{2}}$

$\sf\green { =>{13}^{2} = 84 + 85 \: ans..}$

Hence, $\sf {{13}^{2} }$ is the sum of two consecutive natural numbers which are 84 and 85.