Express the following as trigonometric ratios of some acute angles.
(i) sin 1185° (ii) tan 235°
(iii) sin (- 3333)
(iv) cot (-3888°) (v) tan 458°
(iv) cosec (-60°)
(vii) cos 500° (viii) sec 380°
Answers
Answer:
Step-by-step explanation:
(i) sin 1185° = Sin( 1080 + 105)° = Sin(3 * 360 + 105)° = Sin105°
= Sin(90 + 15)° = Cos 15°
ii) tan 235° = Tan (180 + 55)° = Tan 55°
(iii) sin (- 3333°) = - Sin(3333°) = -Sin(3240 + 93)° = -Sin(360 *9 + 93)°
= - Sin93° = - Sin(90 + 3)° = - (Cos3°) = -Cos3°
(iv) cot (-3888°) = - Cot(3888°) = -Cot(3600 + 288)° = -Cot 288° = -Cot(180 + 108)° = -Cot108° = -Cot(90 + 18°) = -(-Tan18°) = Tan18°
(v) tan 458° = Tan (360 + 98)° = Tan 98° = Tan (90 + 8)° = -Cot8°
(iv) cosec (-60°) = -Cosec60°
(vii) cos 500° = Cos (360 + 140)° = Cos 140° = Cos(180 - 40)° = -Cos40°
(viii) sec 380° = Sec(360 + 20)° = Sec 20°
Step-by-step explanation:
(i) sin 1185 = Sin ( 1080 + 105 )
= Sin ( 3*360 + 105 )
= Sin 105
= Sin ( 90 + 15 ) = Cos 15
(ii) tan 235 = Tan ( 180 + 55 )
= Tan 55
(iii) sin ( -3333 ) = - Sin ( 3333 )
= -Sin ( 3240 + 93 )
= - Sin ( 360 *9 + 93 )
= Sin93 = - Sin (90 + 3) = - ( Cos3)
= - Cos3
(iv) cot ( -3888 ) = -Cot ( 3888 )
= - Cot ( 3600 + 288 ) = -Cot 288
= - Cot ( 180 + 180 ) = -Cot108
= -Cot ( 90 + 18 ) = - ( -Tan18 )
= Tan18
(v) Tan 458 = Tan ( 360 + 98 )
= Tan 98 = Tan ( 90 + 8 )
= -Cot8
(vi) Cosec ( -60 ) = - Cosec60
(vii) Cos 500 = Cos ( 360 + 140 )
= Cos 140 = Cos ( 180 - 40 )
= - Cos ( 180 - 40 )
= - Cos40
(viii) Sec 360 = Sec ( 360 + 20 )
= Sec 20
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