Express the following complex numbers in the form of a + ib:
(7+iX2 – 3i)
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Answer:
hey
Explanation:
We need to saparate real part and imaginary part
(7+I)(2–3i)
We have to multiply both in the form of(a+b)(a-b)
(7+I)(2–3i)
14–21i+2i-3i^2
14–19i-3(—1)
{I^2=—1} I power 2 is equal to —1
14–19i+3
17–19i
Complex number in the form (a+ib)
So we need to convert 17–19i into (a+ib)
-17+19i
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