Express the following cubes as the sum of consecutive odd numbers
a.7 cube
b.8 cube
c.10 cube
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I know only à
Step-by-step explanation:
Let the odd interger be x
therefore,
x+x+2+x+4+x+6+x+8+x+10+x+12 =7³
x+x+2+x+4+x+6+x+8+x+10+x+12= 343 .
7x+42=343
7x=301
x=43
therefore, 43+45+47+49+51+53+55=343
or
43+45+47+49+51+53+55 answer
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