express the following cubes as the sum of consecutive odd number a) 17³
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Let the three numbers be (x−1),x and (x+1).
Given, the sum of three consecutive odd numbers is 15
3
.
⇒15
3
=3375.
∴(x−1)+x+(x+1)=3375
⇒ 3x=3375
⇒ x=1125.
Therefore,
1
st
number =x−1=1125−1=1124.
2
nd
number =x=1125.
3
rd
number =x+1=1125+1=1126.
Hence, the three consecutive numbers are 1124,1125,1126.
Then, 1124+1125+1126=15
3
.
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