express the following in a+ib form
(1+i)(1+3i)/1+5i
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Given, (1+i)(1+3i)/1+5i
we multiply the numerator,
(1+3i+i-3)/1+5i,
(4i-2)/1+5i,
by doing rationalising we get,
(4i-2)/(1+5i) / (1-5i)/(1-5i)
(4i+20-2-20i) / (1+5)
(18-16i)/6
(9-8i)/3
=(9/3)+(-8i/3)
=3+(-8i/3)
It's in the form of a+ib
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