Question

express the following in a+ib form (-√3+√-2) (2√3-i)​

Answer 1

Answer:

(√2-6) +i√3(√2+1)

Step-by-step explanation:

(-√3+√2)(2√3-i)=(-√3+i√2)(2√3-i) =-6+i√3+i2√2√3-isquare√2=-6+i√3(√2+1)+√2=(√2-6)+i√3(√2+1).

Answer 2

a + ib form is: $(-6+\sqrt2)+i(2\sqrt6+\sqrt3)$

Step-by-step explanation:

We are given the following:

$(-\sqrt3+\sqrt{-2}) (2\sqrt3-i)$

We have to express the given expression in the form of $a+ib$

$(-\sqrt3+\sqrt{-2}) (2\sqrt3-i)\\=(-\sqrt{3}+\sqrt{-1}\sqrt2)(2\sqrt3-i)\\=(-\sqrt3+i\sqrt2)(2\sqrt3-i)\\=-6+i\sqrt3+i2\sqrt6-i^2\sqrt2\\=-6+i\sqrt3+i2\sqrt6+\sqrt2\\=(-6+\sqrt2)+i(2\sqrt6+\sqrt3)$

which is the required form.

#Learnmore

Express the following in the standard form a+ib: 2(i−3)(1+i)2

https://brainly.in/question/3809270