Express the following in the form of a+ib
1.(1/1-2i+3/1+i) (3+4i/2-4i)
2.(1+i/1-i)
3.(1+i)^3/4+3i
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Answered by
1
Answer:
Correct option is
C
41+49i.
Simplifying, we get
(1+i−2i+21+i+3−6i)(2−4i3+4i)
(3−i4−5i)(2−4i3+4i)
Hence
3−i4−5i.2−4i3+4i
=6−12i−2i−412+16i−15i+20
=2−14i32+i
=200(32+i)(2+14i)
=20064+448i+2i−14
=20050+450i
=41+9i.
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