Question

Express the following in the form of a+ib
i).(2-3i)(3+4i)
​

Answer 1

Multiplying both numerator and denominator by the Complex conjugate of the denominator

Therefore,

(3+4i)

(2−3i)

=

3+4i

2−3i

×

3−4i

3−4i

=

(3)

2

−(4i)

2

(2−3i)(3−4i)

=

9+16

(6+12i

2

)−(9+8)i

=

25

−6−17i

=

25

−6

+

25

−17

i

Here, A=

25

−6

and B=

25

−17

Answer 2

Answer:

18 - i

Step-by-step explanation:

"I love complex numbers"

(2-3i)(3+4i)

= 2(3) + 2(4i) - (3i)(3) - (3i)(4i)

= 6 + 8i - 9i - 12i²

as i = √(-1)

i² = (-1)

= 6 + 8i - 9i - 12(-1)

= 6 + 8i - 9i + 12

= 18 - i

I hope this answer is correct and will clear your doubt