Question

express the following linear equation. in four of ax+ by + c=o and write value of a,b, and c​

Answer 1

Answer:

(i) 2x + 3y = 9.3\overline { 5 }

(ii) x-\frac { y }{ 5 } -10\quad =\quad 0

(iii) – 2x + 3y = 6

(iv) x = 3y

(v) 2x = -5y

(vi) 3x + 2 = 0

(vii) y – 2 = 0

(viii) 5 = 2x

Solution:

(i) We have 2x + 3y = 9.3\overline { 5 }

or (2)x + (3)y + (-9.3\overline { 5 } ) = 0

Comparing it with ax + by +c= 0, we geta = 2,

b = 3 and c= –9.3\overline { 5 } .

(ii) We have x-\frac { y }{ 5 } -10\quad =\quad 0

or x + (- \frac { 1 }{ 5 }) y + (10) = 0

Comparing it with ax + by + c = 0, we get

a =1, b =- \frac { 1 }{ 5 } and c= -10

(iii) Wehave -2x + 3y = 6 or (-2)x + (3)y + (-6) = 0

Comparing it with ax – 4 – by + c = 0,we get a = -2, b = 3 and c = -6.

(iv) We have x = 3y or (1)x + (-3)y + (0) = 0 Comparing it with ax + by + c = 0, we get a = 1, b = -3 and c = 0.

(v) We have 2x = -5y or (2)x + (5)y + (0) = 0 Comparing it with ax + by + c = 0, we get a = 2, b = 5 and c = 0.

(vi) We have 3x + 2 = 0 or (3)x + (0)y + (2) = 0 Comparing it with ax + by + c = 0, we get a = 3, b = 0 and c = 2.

(vii) We have y – 2 = 0 or (0)x + (1)y + (-2) = 0 Comparing it with ax + by + c = 0, we get a = 0, b = 1 and c = -2.

(viii) We have 5 = 2x ⇒ 5 – 2x = 0

or -2x + 0y + 5 = 0

or (-2)x + (0)y + (5) = 0

Comparing it with ax + by + c = 0, we get a = -2, b = 0 and c = 5.

Step-by-step explanation:

Now Mark me as brainlest