Question

Express the following linear equation in the form of ax+by+c=0 and indicate the values of a, b and c in each case.
(I) 8x+5y-3=0
(ii) 28x-35y=-7
(iii)93x=12-15y
(iv) 2x=-5y
(v) x/3+y/4=7
(vi) y=-3/2x
(vii) 3x+5y=12​

Answer 1

Solution:

(i) 8x+5y-3=0

=>(8)x+(5)y+(-3)=0

ax+by+c=0

Therefore, a=8; b=5; c=(-3)

(ii) 28x-35y=(-7)

=> 28x-35y+7=0

=> (28)x+(-35)y+(7)=0

ax+by+c=0

Therefore, a=28; b=(-35); c=7

(iii) 93x=12-15y

=> 93x+15y-12=0

=> (93)x+ (15)y+(-12)=0

ax+by+c=0

Therefore, a=93; b=15; c=(-12)

(iv) 2x=(-5)y

=> 2x+5y+0=0

=> (2)x+(5)y+(0)=0

ax+by+c=0

Therefore, a=2; b=5; c=0

(v) x/3+y/4=7

=> x/3+y/4-7=0

=> (⅓)x+(¼)y+(-7)=0

ax+by+c=0

Therefore, a=⅓; b=¼; c=(-7)

(vi) y=(-3)/2x

=> 2x+y+3=0

=> (2)x+(1)y+(3)=0

ax+by+c=0

Therefore, a=2; b=1; c=3

(vii) 3x+5y=12

=> 3x+5y-12=0

=> (3)x+(5)y+(-12)=0

ax+by+c=0

Therefore, a=3; b=5; c=(-12)

Sorry, if there are any mistakes.......

Answer 2

Step-by-step explanation:

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