Question

express the following linear equations in the form ax+by+c=0 and indicate values of a, b and c in x-y/5-10=0​

Answer 1

Answer:

here's your answer friend..

Given equation:

Given equation:x−y/5−10=0

Given equation:x−y/5−10=0Rearranging the equation

Given equation:x−y/5−10=0Rearranging the equation 1x + (-1/5)y + (-10) = 0

Given equation:x−y/5−10=0Rearranging the equation 1x + (-1/5)y + (-10) = 0If we compare the equation with ax+by+c=0

Given equation:x−y/5−10=0Rearranging the equation 1x + (-1/5)y + (-10) = 0If we compare the equation with ax+by+c=0Then will get

Given equation:x−y/5−10=0Rearranging the equation 1x + (-1/5)y + (-10) = 0If we compare the equation with ax+by+c=0Then will get⇒a=1,b=−1/5,c=−10

Answer 2

Answer:

1x+(-1/5)y+(-10)=0

ax+ by +c

Here value of a=(1) b=(-1/5) and c=(-10)