Question

express the following on the form of a+ib a,b€Ri find value of a and b(2+3i)(2-3i)​

Answer 1

=> (2+3i) (2-3i)

where :- i = √(-1)

We know that :- (a+b)(a-b) = a²-b²

=> (2+3i) (2-3i)

=> (2)² - (3i)²

=> 4 - 9 (i)²

We know that :- i² = -1

=> 4 - 9 (-1)

=> 4 + 9

=> 13

Therefore , (2+3i) (2-3i) = 13+0i

So, a = 13 and b = 0

Answer :

a = 13

b = 0

Answer 2

★ǫᴜᴇsᴛɪᴏɴ★

Express the following in the form of a = ib, a,bϵR i= √−1. State the values of a and b

(2+3i)(2-3i)

Answer:-

Formula used :-

(a+b) (a-b) = a² - b²

Let's solve the sum

(2+3i)(2-3i)

= 2² - 9i²

= 4 - 9i²

= 4 - 9( - 1)

[ Given, value of i = √-1

∴ i² = -1 ]

= 4 + 9 = 13

So on comparing with a + ib

We get ,

a = 13 and b = 0

@BengaliBeauty

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