Math, asked by ko900990, 2 months ago

Express the given number 2.232323.... can be expressed in the form p /q , where p and q are
integers and q≠ 0.

Answers

Answered by snehanegi066
0

Answer :

x=0.2353535...

x=0.2353535...10x=2.353535...

x=0.2353535...10x=2.353535...100x=23.53535...

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in q

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in qp

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in qp

x=0.2353535...10x=2.353535...100x=23.53535...1000x=235.353535...10x−1000x=2.353535...−235.353535...−990x=−233x= 990233 in qp

Step-by-step explanation:

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