express the greatest 3-digit number as a product of prime
Answers
Answered by
4
999is correct answer
Answered by
7
"999"
is the greatest 3-digit number.
First, prime factorising 999 will give,
999=3*3*3*37
That is, 999/3=333
333/3=111
111/3=37
Now,
999=3*3*3*37
This is the expression which shows the greatest 3-digit number as a product of prime, as 3&37 are prime nos.
Similar questions