Express the greatest 3 digit number as a product of primes
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Answered by
0
Answer:
Greatest 3 digit number=999
by doing its prime factorisation method
3║999
3║333
111║111
║1
999=3x3x111
this is the prime factorisation of 999.
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Answered by
6
Answer:
999= 3 × 3 × 3 × 37
Step-by-step explanation:
999= 3 × 333
333=3 × 111
111=3 × 37
37= 37 × 1
999= 3 × 3 × 3 × 37
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