Express the greatest 3-digit number as a product of primes.
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Answered by
1
Step-by-step explanation:
The largest 3 digit number is 999
If you wants its products of prime do the prime factorization.
so its prime factors are 3,3,3,37
=》3*3*3*37
Answered by
0
Answer:
The greatest 3 digit number is 999.
3 | 999
3 | 333
3 | 111
Therefore, 999 = 3 x 3 x 111
HOPE MY ANSWER HELPED!!!
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