express the greatest 3-digit number as a product of primes
Answers
Answered by
3
The greatest 3-digit number is 999
Hence,
999=3*3*3*37
Hence,
999=3*3*3*37
Answered by
0
Answer:Do Prime Factorization First
Step-by-step explanation:1st Answer is 3 x 3 x 111 or 3 x 3 x 37
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