express the hcf of 210 and 55 as 210x+55y where x,y are integers in two different ways.
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Answered by
12
hi!
here is your answer.
210 = 5 × 3 × 7×2
55 = 5 × 11
here...
H.C.F = 5
H.C.F also can be expressed as 210x +55.
5 = 210x +55y
210x + 55y = 5
[dividing throughout by 5]
42x + 11y = 1
hence expressed !
hope this helps !!#
here is your answer.
210 = 5 × 3 × 7×2
55 = 5 × 11
here...
H.C.F = 5
H.C.F also can be expressed as 210x +55.
5 = 210x +55y
210x + 55y = 5
[dividing throughout by 5]
42x + 11y = 1
hence expressed !
hope this helps !!#
Answered by
0
Answer:
this is not a complete answer
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