Question

express the hcf of 210 and 55 as 210x+55y where x,y are integers in two different ways.

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Abhijeet007
Secondary SchoolMath 5+3 pts


Express the hcf of 210 and 55 as 210x+55y where x,y are integers in two different ways.
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Abhijeet007

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pratik40
Pratik40 Ace
hi!
here is your answer.

210 = 5 × 3 × 7×2

55 = 5 × 11

here...
H.C.F = 5

H.C.F also can be expressed as 210x +55.

5 = 210x +55y

210x + 55y = 5

[dividing throughout by 5]

42x + 11y = 1

hence expressed !

hope this helps !!#