Express the HCF of 468 and 222 as 468 x+222y where x and y are integers
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First of all, take the HCF of 468 and 222 by prime factorization method.
It will be 2*3 i.e. 6.
Now we have to express 6 as the sum of two numbers which are 468 x and 222 y. As the numbers are quite large, we will have to reduce them in order to get 6.That means, we will have to take x and y as fractions so that they can lower the values of 468 and 222.
So we take x as 1/117 which will reduce 468 to 4 and we take y as 1/111 which will reduce 222 to 2.
468*1/117 + 222*1/111 = 4+2 =6
It will be 2*3 i.e. 6.
Now we have to express 6 as the sum of two numbers which are 468 x and 222 y. As the numbers are quite large, we will have to reduce them in order to get 6.That means, we will have to take x and y as fractions so that they can lower the values of 468 and 222.
So we take x as 1/117 which will reduce 468 to 4 and we take y as 1/111 which will reduce 222 to 2.
468*1/117 + 222*1/111 = 4+2 =6
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