Question

Express the HCF of 48 and 18 as a linear combination

Answer 1

Answer:

Step-by-step explanation:

According to the question

A=bq +r ,

48= 18x2+12

18=12x1+6

12=6x2+0

Therefore the HCF can be (18,68)

That is =6

6=-18-12x1

6= 18- (48-18x12)

6= 18-48x1+18x2

6=18x3-48x1

:6=18x3+48x(-1)

Therefore......,............6=18x+18y

6=13x3 +48x(-1)

That is 18 x3+48(-1)+18x48-18x48

6=18x+48

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Hope it helps