Express the kinetic energy in KJ when a bike of 80 kg moving with a velocity of 72km h-1
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Answered by
50
Kinetic Energy K=1/2 * m * v²
m=80 kg
v= 72 km/h= 20 m/s
K=1/2 * m * v²
∴K=1/2 * 80* 20²
= 40*400
= 16000 J
1 KJ= 1000 J
So 16000 J= 16 KJ
m=80 kg
v= 72 km/h= 20 m/s
K=1/2 * m * v²
∴K=1/2 * 80* 20²
= 40*400
= 16000 J
1 KJ= 1000 J
So 16000 J= 16 KJ
dhanvi:
thanks
Answered by
25
⇒ m = 80 kg
⇒ v = 72 × 5/18 = 20 m/s
⇒ Ek = 1/2 mv²
⇒ Ek = 1/2 × 80 × 20 × 20
⇒ Ek = 32000/2 = 16000J
⇒ Ek = 16kJ
⇒ v = 72 × 5/18 = 20 m/s
⇒ Ek = 1/2 mv²
⇒ Ek = 1/2 × 80 × 20 × 20
⇒ Ek = 32000/2 = 16000J
⇒ Ek = 16kJ
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