Physics, asked by bindureddy2407, 3 months ago

express the kinetic energy of electron wavelength the de broglie of one ampere​

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Answered by charanisathvika
0

Answer:

For an electron with KE = 1 eV and rest mass energy 0.511 MeV, the associated DeBroglie wavelength is 1.23 nm, about a thousand times smaller than a 1 eV photon.

Answered by pr3023
0

Hope it helps you have a great day :-)

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