Express the length and breadth of rectangle whose area is xsquare+3x+2
Answers
Answered by
2
We know,
Area of Rectangle = l × b
l = Length
b = Breadth
According to Question,
l × b = x² + 3x + 2
⇒ l × b = x² + (2 + 1)x + 2
⇒ l × b = x² + 2x + x + 2
⇒ l × b = x(x + 2) + 1(x + 2)
⇒ l × b = (x + 2) × (x + 1)
Hence,
Length (l) = (x + 2)
Breadth (b) = (x + 1)
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Area of Rectangle = l × b
l = Length
b = Breadth
According to Question,
l × b = x² + 3x + 2
⇒ l × b = x² + (2 + 1)x + 2
⇒ l × b = x² + 2x + x + 2
⇒ l × b = x(x + 2) + 1(x + 2)
⇒ l × b = (x + 2) × (x + 1)
Hence,
Length (l) = (x + 2)
Breadth (b) = (x + 1)
✪ Be Brainly ✪
Answered by
5
Given :
Area of the rectangle = x² +3 x +2
To Find :
Dimensions
Solution :
We have to make its factor and those factors are it's dimensions.
We can make its factors by mid term spilting :
x²+3x+2
Multiplication = 2x²
Sum = 3x
Those two special numbers are = 1x and 2x .
=> x²+2x+1x+2
x(x+2)+1(x+2)
(x+2)(x+1)
The required dimensions are (x+2)(x+1) .
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