Express the linear equation y-2=9 in the form aX + bY + c = 0 and find the value of a,b and c...
Answers
Answer:
5
Step-by-step explanation:
(i) 2x+3y=9.3
5
ˉ
⇒2x+3y−9.3
5
ˉ
Comparing the equation with ax+by+c=0
a=2,b=3,c=−9.3
5
ˉ
(ii) x−
5
y
−10=0
Comparing the equation with ax+by+c=0
a=1,b=−
5
1
,c=−10
(iii) −2x+3y=6
⇒−2x+3y−6=0
Comparing the equation with ax+by+c=0
a=−2,b=3,c=−6
(iv) x=3y
⇒x−3y=0
Comparing the equation with ax+by+c=0
a=1,b=−3,c=0
(v) 2x=−5y
⇒2x+5y=0
Comparing the equation with ax+by+c=0
a=2,b=5,c=0
(vi) 3x+2=0
⇒3x+0y+2=0
Comparing the equation with ax+by+c=0
a=3,b=0,c=2
(vii) y−2=0
⇒0x+y−2=0
Comparing the equation with ax+by+c=0
a=0,b=1,c=−2
(viii) 5=2x
⇒−2x+0y+5
Comparing the equation with ax+by+c=0
a=−2,b=0,c=5
Answer:
(i) 2x+3y=9.3
5
ˉ
⇒2x+3y−9.3
5
ˉ
Comparing the equation with ax+by+c=0
a=2,b=3,c=−9.3
5
ˉ
(ii) x−
5
y
−10=0
Comparing the equation with ax+by+c=0
a=1,b=−
5
1
,c=−10
(iii) −2x+3y=6
⇒−2x+3y−6=0
Comparing the equation with ax+by+c=0
a=−2,b=3,c=−6
(iv) x=3y
⇒x−3y=0
Comparing the equation with ax+by+c=0
a=1,b=−3,c=0
(v) 2x=−5y
⇒2x+5y=0
Comparing the equation with ax+by+c=0
a=2,b=5,c=0
(vi) 3x+2=0
⇒3x+0y+2=0
Comparing the equation with ax+by+c=0
a=3,b=0,c=2
(vii) y−2=0
⇒0x+y−2=0
Comparing the equation with ax+by+c=0
a=0,b=1,c=−2
(viii) 5=2x
⇒−2x+0y+5
Comparing the equation with ax+by+c=0
a=−2,b=0,c=5
Step-by-step explanation:
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