Math, asked by manirithvik18, 7 months ago

Express the nature of the roots of the quadratic equation 3x2 - 2x +1/3= 0​

Answers

Answered by bittu02
2

Answer:

x = 0 roots are real and equal because ,

1st we find discriminant which is equal to b²- 4ac

D = b² - 4ac

where , a = 3

b = 2

c = 1/3

D = b² - 4ac

D = (2)² - 4×3×1/3

D = 0

therefore roots are real and equal because ,

Roots are 0,0

Answered by Nihar1729
2

Answer:

the roots are real,equal and rational.

Step-by-step explanation:

  • we have a quadratic equation:
  • 3x²-2x+1/3=0
  • here, a = 3
  • b = -2
  • c = 1/3
  • now discriminant,(D) is: \sqrt{b^2 - 4ac}
  • by putting the values in (D), we get,
  • \sqrt{(-2)^2-4(3)(1/3)}
  • \sqrt{4-4}
  • 0
  • here , we get , D=0
  • therefore,the roots are real,equal and rational.(Ans.)
  • and roots are (-b±D)/2a
  • so roots are (-(-2)±0)/2*3
  • α=1/3
  • β=1/3
  • thank u.........
  • please mark as brainliest
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