Express the odd number by using euclid's division Lemma
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Any number which can be written in the form of 2n+1 is called odd number.
I think u needed this mate.
I think u needed this mate.
shaivaj67:
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HOLA
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Let n be an odd number
On dividing n by 3 , we get quotient m and remainder r such that
a = bq + r
n = 3q + r. where , 0 > r > 3
So we have , n = 3q , 3q + 1 , 3q + 2 , 3q + 3
[•] When , n = 3q
n is clearly odd
[•] When , n = 3q + 2
n is clearly odd
(:) But when , n = 3q + 1 , 3q + 2 , 3q + 3 its even
[•] So when odd numbers are expressed by euclids division lemma we have 3q , 3q + 2
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HOPE U UNDERSTAND ❤❤❤❤
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Let n be an odd number
On dividing n by 3 , we get quotient m and remainder r such that
a = bq + r
n = 3q + r. where , 0 > r > 3
So we have , n = 3q , 3q + 1 , 3q + 2 , 3q + 3
[•] When , n = 3q
n is clearly odd
[•] When , n = 3q + 2
n is clearly odd
(:) But when , n = 3q + 1 , 3q + 2 , 3q + 3 its even
[•] So when odd numbers are expressed by euclids division lemma we have 3q , 3q + 2
==============================
HOPE U UNDERSTAND ❤❤❤❤
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