Question

express the ratio energy density of electric field to the energy density of magnetic field is unity .
​

Answer 1

Answer:

Answer: For the electric field, the energy density is

\begin{displaymath}

w_E = \frac{1}{2}\,\epsilon_0\,E^2 =

(0.5)\,(8.85\times 10^{-12}) \,(2.0\times 10^6)^2 = 18\,\,{\rm J\,m}^{-3}.

\end{displaymath}

For the magnetic field, the energy density is

\begin{displaymath}

w_B = \frac{1}{2} \,\frac{B^2}{\mu_0} = \frac{(0.5)\,(1.0\times 10^{-2})^2}

{(4\pi\times 10^{-7})} = 40\,\,{\rm J\,m}^{-3}.

\end{displaymath}

The net energy density is the sum of the energy density due to the electric field and the energy density due to the magnetic field:

\begin{displaymath}

w = w_E + w_B = (18 + 40) = 58\,\,{\rm J\,m}^{-3}.

\end{displaymath}

Explanation:

f conduct hota hai official the notes of practical i