express the ration cosA , tan A and secA in term of sin A?
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Step-by-step explanation:
cosA=
1−sin
2
A
→(1)
as, cos
2
θ+sin
2
θ=1
tanA=
cosA
sinA
=
1−sin
2
A
sinA
( from (1) )
& secA=
cosA
1
=
1−sin
2
A
1
( From (1) )
so, cosA=
1−sin
2
A
,tanA=
1−sin
2
A
sinA
& secA=
1−sin
2
A
1
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