Question

: Express the ratios cos A, tan A and sec A in terms of sin A.



guys can u find what is the answer? ​

Answer 1

Answer:

$cos ^{2}A + sin ^{2} A = 1 \\ cos ^{2}A = 1 - sin ^{2} A \\ cosA = \sqrt{1 -sin ^{2} A}$

$secA = 1 \div cos A \\ secA = 1 \div \sqrt{ 1 - sin^{2} A }$

$tan ^{2} A = sin ^{2} A \div cos ^{2}A \\ tan ^{2} A = sin ^{2} A \div 1 -sin ^{2} A \\ tanA = 1 \div \sqrt{1 - sin ^{2} A}$

hope I helped

Answer 2

Answer:

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