Question

express the ratios cos A ,tan A and sec A in terms of sin A​

Answer 1

$\cos( \alpha ) = \sqrt{1 - { \sin}^{2} \alpha }$

$\tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \frac{ \sin( \alpha ) }{ \sqrt{1 - { \ \sin }^{2} \alpha } }$

$\sec( \alpha ) = \frac{1}{ \cos( \alpha ) } = \frac{1}{ \sqrt{1 - { \sin }^{2} \alpha } }$

Answer 2

Answer:

cos A= $\sqrt{1-sin^{2} A}$

tan A=$\frac{sin A}{\sqrt{1-sin^{2} A} }$

sec A=$\frac{1}{cos A}$=$\frac{1}{\sqrt{1-sin^{2} A}}$