Express the ratios cosA,tanA & secA in terms of sinA?
Answers
Answered by
86
Heya!!!
cos A
=====
sin^2 A + cos^2 A= 1
cos^2 A = 1 - sin^2 A
cos A = root of (1-sin^2 A)
=====================
tan A
=====
tan A = sin A / cos A
=sinA / root of ( 1- sin^2 A)
======================
sec A
=====
sec A = 1 / cos A
=1/ root of (1-sin^2 A)
==================
HOPE IT HELPS!
cos A
=====
sin^2 A + cos^2 A= 1
cos^2 A = 1 - sin^2 A
cos A = root of (1-sin^2 A)
=====================
tan A
=====
tan A = sin A / cos A
=sinA / root of ( 1- sin^2 A)
======================
sec A
=====
sec A = 1 / cos A
=1/ root of (1-sin^2 A)
==================
HOPE IT HELPS!
Answered by
76
The answer to your question has been attached just below.
__________________________
Hope it helps :)
__________________________
Hope it helps :)
Attachments:
Similar questions