Question

Express the ratios cosA,tanA & secA in terms of sinA?

Answer 1

Heya!!!

cos A
=====

sin^2 A + cos^2 A= 1

cos^2 A = 1 - sin^2 A

cos A = root of (1-sin^2 A)

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tan A
=====

tan A = sin A / cos A

=sinA / root of ( 1- sin^2 A)

======================

sec A
=====

sec A = 1 / cos A

=1/ root of (1-sin^2 A)

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HOPE IT HELPS!

Answer 2

The answer to your question has been attached just below.
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Hope it helps :)