Express the ratios of sin A ,cos A , tan A in terms of sec A
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1)cos A =1/secA
2) We know sin^2A+ cos^2A=1
we can write it as sin^2A + 1/sec^2A=1
sin^2A= 1 - 1/sec^2A
So sinA = √(1 - 1/sec^2A)
on simplifying
= {√(sec^2A - 1)} / secA
3) tanA = sinA/cosA
=【{√(sec^2A - 1)} / secA】/ 【{1/secA}】
on simplifying
=√(sec^2A - 1)
hope it helped....☺☺
2) We know sin^2A+ cos^2A=1
we can write it as sin^2A + 1/sec^2A=1
sin^2A= 1 - 1/sec^2A
So sinA = √(1 - 1/sec^2A)
on simplifying
= {√(sec^2A - 1)} / secA
3) tanA = sinA/cosA
=【{√(sec^2A - 1)} / secA】/ 【{1/secA}】
on simplifying
=√(sec^2A - 1)
hope it helped....☺☺
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