Express the relation between conductivity and molar conductivity of a solution held in a cell?
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Answered by
104
∧m=K×1000/M
K=kappa=conductivity
M=molarity
Molar conductivity:Molar conductivity of a solution is given by concentration of volume of a solution containing 1 mole of the electrolyte kept between two electrodes with the area of cross-section A & distance of unit length.
∧m=kA/l
Now,l=1 & A=V(Volume containing 1 mole of the electrolyte.)
Therefore;∧m=kV
Molar conductivity increases with a decrease in concentration.This is because the total volume V of the solution containing one mole of the electrolyte increases on dilution.
K=kappa=conductivity
M=molarity
Molar conductivity:Molar conductivity of a solution is given by concentration of volume of a solution containing 1 mole of the electrolyte kept between two electrodes with the area of cross-section A & distance of unit length.
∧m=kA/l
Now,l=1 & A=V(Volume containing 1 mole of the electrolyte.)
Therefore;∧m=kV
Molar conductivity increases with a decrease in concentration.This is because the total volume V of the solution containing one mole of the electrolyte increases on dilution.
Answered by
45
Answer:
Ʌm = К/c
Here, c = concentration in moles per volume, К = specific conductivity and Ʌm = molar conductivity. As the solution contains only one mole of electrolyte, the above equation can be modified as:
Ʌm = КV
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