Question

Express the square of 9 as the sum of odd numbers

Answer 1

HEY MATE,

HERE IS YOUR ANSWER.

9^2=81

(81 AS SUM OF ODD NUMBERS)=1+3+5+7+9+11+13+15+17

HOPE IT HELPS...

MARK AS BRAINLIEST.

REGARDS,

GUNJAN.

Answer 2

Answer:

Concept:

Odd Numbers:

• Odd numbers are those that cannot be evenly divided by two.
• A remainder is produced when an odd number is divided by two.
• It is impossible to evenly divide it into two separate integers.  
• Example: 1, 3, 5, 7.

Square Numbers:

• A "Square Number" is the product of multiplying an integer or number (not a fraction) by itself.
• For instance, 9 times of 9 is equal to 81.

Given:

Square of 9.

To Find:

We need to express the square of 9 as the sum of odd numbers.

Solution:

We know that the square of 9 is,

$9^{2} = 9 * 9 = 81$

Sum of First 3 odd numbers,

$1+3+5 = 9$

Sum of First 4 odd numbers,

$1+3+5+7 = 16$

Sum of first 5 odd numbers,

$1 + 3 + 5+7+9 = 25$

Sum of First 6 odd numbers,

$1 + 3 + 5+7+9+11 = 36$

Sum of First 7 odd numbers,

$1 + 3 + 5+7+9+11 +13= 49$

Sum of First 8 odd numbers,

$1 + 3 + 5+7+9+11 +13+15= 64$

Sum of First 9 odd numbers,

$1 + 3 + 5+7+9+11 +13+15+17=81$

Therefore, the expression of the square of 9 as the sum of odd numbers  is $9^{2} =81= 1 + 3 + 5+7+9+11 +13+15+17$ .

#SPJ3