Question

Express the terms of factors by
factor tree method, ab² +5a²b -ab​

Answer 1

Answer:

The correct answer is "a+b-2" and "a+b-3".

Step-by-step explanation:

\begin{gathered}The \ given \ expression \ is:\\\\(a+b)^2-5a-5b+6\\(a+b)^2-5(a-b)+6\\\\Let (a+b)=x,\\\\=x^2-5x+6\\\\text{\O}n \ factorizing \ the \ above \ equation ,we \ get\\\\=x^2-3x-2x+6\\\\=x(x-3)-2(x-3)\\\\=(x-2)(x-3)\\\\text{\O}n \ putting \ x=(a+b),we get\\\\(a+b-2) \ and \ (a+b-3)\end{gathered}

The given expression is:

(a+b)

2

−5a−5b+6

(a+b)

2

−5(a−b)+6

Let(a+b)=x,

=x

2

−5x+6

text\On factorizing the above equation,we get

=x

2

−3x−2x+6

=x(x−3)−2(x−3)

=(x−2)(x−3)

text\On putting x=(a+b),weget

(a+b−2) and (a+b−3)