Question

express the trignmetric ratios sin A, sec A and tan A in trlerms of cot A.​

Answer 1

Answer:

For tan A

$\tan(a ) = \frac{1}{ \cot(a) }$

Answer 2

Answer:

Sin A

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sin A= 1/(cosecA)

=1/(√{cot^2A +1}). [1+cot^2= cosec^2A]

SecA

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secA=√{1+ tan^2A}

=√{1+1/cot^2A}

=√{(cot^2A+1)/cot^2A}

√{cotA+1}/cotA

TanA

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tanA=1/cotA