Question

express the Trignomertic ratios cos A, tan A and cot A in terms of sec A​

Answer 1

Answer:

this is a more points right right

Answer 2

Answer:

cosec2A−cot2A=1

⇒cosec2A=1+cot2A

⇒(cosecA)2=cot2A+1

⇒(sinA1)2=cot2+1

⇒(sinA)2=cot2A+11

⇒sinA=±cot2A+11

We reject the negative value of sinA for acute angle A. Therefore sinA=cot2A+11

2]tanA=cotA1

3]We have sec2A−tan2A=1

⇒sec2A=1+tan2A

⇒sec2A=1+cot