Question

Express the trigonometric ratio of ""Sin A"" in terms of ""Cot A"".

Answer 1

• We are asked to express the trigonometric ratio of Sin A in terms of Cot A.

We know that Cosec A is the reciprocal of Sin A.

So, Sin A can be written as $\sf{ \dfrac{1}{cosecA} }$

$\dag{ \: \: \: \: \: \boxed{\sf{ \red{ { cot }^{2} A + 1 = {cosec}^{2} A}}}}$

So, we can write it as $\sf{sinA = \dfrac{1}{cosecA} = \dfrac{1}{ \sqrt{1 + {cot}^{2}A } } }$

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Trigonometric ratios pdh lo bhai, nahi to kuch samajh nahi aane wala xD xD

Let me give you few trigonometric identities, thank me later ;)

$\longrightarrow{ \sf{ \sin^{2} \theta + \cos^{2} \theta = 1}}$

$\longrightarrow{ \sf{1 + \tan^{2} \theta = \sec^{2} \theta}}$

$\longrightarrow{ \cot^{2} \theta + 1 = \cosec ^{2} \theta}$

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