express the trigonometric ratio sinA in terms of cosA
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To express the trigometric ration sinA in term of cosA
By using property of trignometry
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There you go :-
cos a = square root of (1- square of sin a)
tan = sin a / cos a = sin a/(square root of (1- square of sin a))
cosec a = 1/sin a
sec a = 1/cos a = 1/(square root of (1- square of sin a))
cot a = cos a /sin a = (square root of (1- square of sin a))/sin a
mark brainest,
cos a = square root of (1- square of sin a)
tan = sin a / cos a = sin a/(square root of (1- square of sin a))
cosec a = 1/sin a
sec a = 1/cos a = 1/(square root of (1- square of sin a))
cot a = cos a /sin a = (square root of (1- square of sin a))/sin a
mark brainest,
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