Question

express the trigonometric ratios sin A ,sec A and tan A in terms of cot A.

Answer 1

1)sinA=cosA/cotA
2)secA=√(1+tan^2A)
3)tanA=1/cotA

Answer 2

Solution:

(1) We know that 

cosec^2A − cot^2A = 1

⇒ cosec^2A = 1+ cot^2A

⇒cosecA= 1 ÷ (√1+cot^2A)

 ⇒ sinA =1 ÷ (√1+cot2A)           

{ °•° sinA=1 ÷ cosecA }

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(2) We know that 

sec^2A −tan^2A = 1

⇒sec^2A=1+tan^2A

⇒sec^2A =1+1 ÷ cot^2A

=cot^2A+1 ÷ cot^2A

⇒secA= (√1+cot^2A) ÷ cotA

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(3) We know that tanA=1 ÷ cotA

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➡ plz Note :- " ^ " it means square !!

( for example $sin^{2}{A}$ = sin^2A )

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