Express the trigonometric ratios sin A, sec A and tan A in terms of cot A
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Solution:
(1) We know that
cosec^2A − cot^2A = 1
⇒ cosec^2A = 1+ cot^2A
⇒cosecA= 1 ÷ (√1+cot^2A)
⇒ sinA =1 ÷ (√1+cot2A)
{ °•° sinA=1 ÷ cosecA }
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(2) We know that
sec^2A −tan^2A = 1
⇒sec^2A=1+tan^2A
⇒sec^2A =1+1 ÷ cot^2A
=cot^2A+1 ÷ cot^2A
⇒secA= (√1+cot^2A) ÷ cotA
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(3) We know that tanA=1 ÷ cotA
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➡ plz Note :- " ^ " it means square !!
( for example = sin^2A )
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